How to find the Inverse of a Cube Root Function #Shorts
0:58
How to find the Inverse of a Cube Root Function #Shorts
5.7K viewsNov 2, 2020
YouTubeProf. Redden
Find the domain of the function 𝑓(𝑥)= 𝑠𝑖𝑛^(−1) (𝑥^2−4). Also, find its range.#inversetrigonom
2:06
Find the domain of the function 𝑓(𝑥)= 𝑠𝑖𝑛^(−1) (𝑥^2−4). Also, find its range.#inversetrigonom
4.6K views3 months ago
YouTubeShivang Maths Academy
Q) Solve for 𝑥, 2tan^(−1) 𝑥+sin^(−1) (2𝑥/(1+𝑥^2 ))=4√3 #inversetrigonometry #maths #cbsemaths
1:33
Q) Solve for 𝑥, 2tan^(−1) 𝑥+sin^(−1) (2𝑥/(1+𝑥^2 ))=4√3 #inversetrigonometry #maths #cbsemaths
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YouTubeShivang Maths Academy
The simplest form of tan^(−1) [(√(1+x)−√(1−x))/(√(1+x)+√(1−x))] is (a π/4−x/ #cbsemaths #maths
2:33
The simplest form of tan^(−1) [(√(1+x)−√(1−x))/(√(1+x)+√(1−x))] is (a π/4−x/ #cbsemaths #maths
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Determine the Inverse of F(x): Step-by-Step Method
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Determine the Inverse of F(x): Step-by-Step Method
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Q) Find dy/dx, if y=tan^(−1) ((1+sinx)/cosx) #cbseclass12 #cbse2026 #maths # #mathsschool
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Q) Find dy/dx, if y=tan^(−1) ((1+sinx)/cosx) #cbseclass12 #cbse2026 #maths # #mathsschool
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Q) Simplify : .cos^(−1) ((sin𝑥+cos𝑥)/√2),𝜋/4=𝑥=5𝜋/4 #shivangmathsacademy #maths #cbsemaths
2:16
Q) Simplify : .cos^(−1) ((sin𝑥+cos𝑥)/√2),𝜋/4=𝑥=5𝜋/4 #shivangmathsacademy #maths #cbsemaths
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Fundamental Theorem of Calculus Part 1: Why Derivative and Integral Are Inverses
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Q) If 𝑠𝑖𝑛 𝑐𝑜𝑡^(−1) (𝑥+1)]=𝑐𝑜𝑠(tan^(−1) 𝑥), 𝑡ℎ𝑒𝑛 𝑓𝑖𝑛𝑑 𝑥.#class12maths #shivang
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Q) If y=tan^(−1) ((1−cosx)/sinx), then dy/dx is equal to #continuity_and_differentiability #maths
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Q) Differentiate y=log(𝑥+√(𝑥^2+a^2 )) w.r.t. 𝑥.#cbseclass12 #cbse2027 #maths #cbse # #maths
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