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Limit and Continuity
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Continuity of Piecewise Functions — Determining Continuity
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Q) If 2cos^(−1) x=y, then dy/dx is #continuity_and_differentiability #maths #cbsemaths #cbse2027
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Find k so that 𝑓(𝑥)={((𝑥^2−2𝑥−3)/(𝑥+1), 𝑥≠−1 𝑘, 𝑥=−1) is continuous at x=−1.#cbse2027 #maths
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Q) Find the value of k, so that f(x)={ ((kcos x)/(𝜋−2x),if x≠𝜋/2 3, if x=𝜋/2) is contin
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If 𝑓(𝑥)={ ((sin^2 𝑎𝑥)/𝑥^2 if 𝑥≠0 1 , if 𝑥=0) is continuous at 𝑥=0, then the value of ' 𝑎 ‘
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CSIR NET & IIT JAM | Function of Two Variables | Complete One Shot Series
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Q) If sin^(−1) 𝑥=𝑦,then 𝑑𝑦/𝑑𝑥 is #maths #continuityanddifferentiabilityclass12 #class12 #cbse
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Q) If 𝑦=cos^(−1){(2𝑥−3√(1−𝑥^2 ))/√13}, find 𝑑𝑦/𝑑𝑥. #maths #cbse2027 #cbse #continuityanddif
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Q) If e^y (x+1)=1, prove that dy/dx=−e^y #cbseclass12 #cbse2027 #maths # #cbsenotes
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Find the values of 𝛌 if the function 𝐟(𝐱)={((〖𝐬𝐢𝐧^𝟐 𝛌𝐱)/𝐱^𝟐 , 𝐢𝐟 𝐱≠𝟎 𝟏, 𝐢𝐟 𝐱=𝟎)
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Q) If e^(𝑥+y)=3𝑥, then dy/d𝑥 is #maths #differentiation #cbse2026 #cbse2027
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Today, I had the privilege of sharing my story as part of Global Kinship Care Week with Kinship Care Ireland. It was a deeply meaningful day of reflection, recognition and celebration, honouring the grandparents, relatives and family friends who step forward to care for children when their parents are unable to do so. I am incredibly honoured to have been invited as one of today’s guest speakers and to use my own experience to help shine a light on the realities faced by kinship families. Kinshi
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Q) If 𝑦=sin(𝑥+𝑦) and 𝑑𝑦/𝑑𝑥=0, then prove that 𝑦=±1.#class12maths
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A 7-joint robot arm can have more solutions than you need. The challenge is choosing the right one. 🤖🧠 This visual servoing demo from Embodied.dev shows how redundant inverse kinematics can keep a robot’s motion continuous while tracking a moving target. Instead of letting the arm suddenly jump between different IK solutions, the system uses the robot’s extra degree of freedom to maintain a smoother, more consistent motion. 👁️ Stereo vision detects the target 🧮 IK calculates possible configu
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Continuity test SUTT adalah pengujian untuk memastikan keterhubungan listrik (kontinuitas) penghantar SUTT dari satu titik ke titik lainnya tidak terputus, terutama setelah pekerjaan stringing, sagging, jointing, atau pemasangan jumper. Tujuannya antara lain: Memastikan konduktor terhubung secara kontinu dari ujung ke ujung. Memastikan jumper, joint, dan clamp terpasang dengan benar. Mendeteksi adanya konduktor putus atau sambungan yang tidak sempurna. Memastikan setiap fasa (R, S, T) sesuai dan
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